What are the dimensions of this rectangle?
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Answer:
F:53cm by 102cm
Step-by-step explanation:
The perimeter of a rectangle can be seen as 2l + 2w, with the length being l, and the width being d. If the ratio is 3:2, then 3+2= 5 parts would be the sum of the length and the width, This is half of the perimeter 2(l+w), so 510÷2 = 255. One part would be 255÷5=51.
If you put it into the ratio, effectively it is:
Length:Width
3×51:2×51
153 :102
Therefore the dimensions are 153cm by 102cm, which is F.