Respuesta :
Answer: Hi. I am sorry if this is a late answer, but here are the answer's I have. I just took the test so I am pretty sure these are correct:
#1.
2(5^e)
#3.
B) f(t)=478(0.935)^t
I am so sorry but I don't have the answer for question #2. I hope you figure it out or someone else can help you. I hope I helped. Good Luck!
Answer:
1) [tex]j=2(5)^e[/tex]
2) option A
3) option B
Step-by-step explanation:
1) Given: The ordered pairs model an exponential function, where j is the function name and e is the input variable.
{(1, 10), (2, 50), (3, 250), (4, 1250)}
Let an exponential function [tex]y=ab^x[/tex]
Now, put (1,10) ⇒10=ab .....(1)
put (2,50) ⇒[tex]50=ab^2[/tex] ....(2)
divide (1) and (2)
we get b=5 then put back in (1)
we get 10=a(5)⇒ a=10/5= 2
therefore the required function is [tex]y=2(5)^x[/tex]
For j is the function name and e is the input variable
the function is [tex]j=2(5)^e[/tex]
2) Given: The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.
To find: What function equation represents the population of the pack of wolves after t years
solution : [tex]f(t) = P(1+r)^t[/tex]
where P-population , r- growth rate , t -time
putting value we get, [tex]f(t) = 88(1+0.025)^t[/tex]
[tex]f(t) = 88(1.025)^t[/tex]
therefore, option A is correct
3) Given: Ramon bought a bicycle for $478. The value of the bicycle is expected to decrease at a rate of 6.5% each year.
To find: What function equation represents the value of the bicycle after t years.
solution : [tex]f(t) = P(1-r)^t[/tex]
where P-population , r- decay rate , t -time
putting values we get, [tex]f(t) = 478(1-0.65)^t[/tex]
[tex]f(t) = 478(0.935)^t[/tex]
therefore, option B is correct
