A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
(a) 0.5 Wb
(b) 12.5 Wb
(c) zero
(d) 2 Wb​

Respuesta :

  • Current=2.5A=I
  • Inductance=B=5H

We know

[tex]\boxed{\sf Magnetic\:flux=\O=BA}[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow \O=5(2.5)[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow \O=12.5Wb[/tex]

Explanation:

Magnetic flux = L I

= 5(2.5)

= 12.5 Wb

(b) 12.5 Wb