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An object starts from rest with constant acceleration of 8m/s2

along a straight line. Find The distance travelled during the 5th second.

Respuesta :

  • Initial velocity=u=0m/s
  • Acceleration=a=8m/s^2
  • Time=t=5s
  • Distance=s=?

Using second equation of kinematics

[tex]\boxed{\sf s=ut+\dfrac{1}{2}at^2}[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow s=0(5)+\dfrac{1}{2}(8)(5)^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow s=4(25)[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow s=100m[/tex]

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