In the triangle above, the cosine of a is 0.8.What is sine of b?
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Answer:
sin b = 0.8
Step-by-step explanation:
Since a and b are complementary angles , then
sin b = cos a = 0.8
The sine of angle b is 0.8
"It is a triangle in which one of the angle measures 90° "
"It is the longest side of the right triangle."
"In a right triangle, sine of angle [tex]\theta[/tex] is the ratio of the opposite side of angle [tex]\theta[/tex] to the hypotenuse."
"In a right triangle, cosine of angle [tex]\theta[/tex] is the ratio of the adjacent side of angle [tex]\theta[/tex] to the hypotenuse."
"Two angles are complementary if the sum of their measures is equal to 90 degrees."
For given question,
We have been given a right triangle.
here,
∠a + ∠b = 90°
∠b = 90° - ∠a ................(i)
This means, a and b are complementary angles.
The cosine of a is 0.8
cos(a) = 0.8
We need to find the sine of angle b.
sin(b)
= sin(90 - a) .............(from (i))
= cos(a) .............(Since [tex]sin(90-\theta)=cos(\theta)[/tex])
= 0.8 ............(Given)
So, sin(b) = 0.8
Therefore, the sine of angle b is 0.8
Learn more about the sine angle here:
brainly.com/question/13256520
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