0.0101 = 1.01% probability that your friend wins the first prize and you win the second prize.
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A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
Event A: Your friend wins the first prize.
Event B: You win the second prize.
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Probability friend wins first prize:
10 out of 100 tickets, so:
[tex]P(A) = \frac{10}{100}[/tex]
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Probability you win second prize:
There will be 99 tickets remaining(1 has been sorted), you have then of then, so:
[tex]P(B) = \frac{10}{99}[/tex]
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What is the probability that your friend wins the first prize and you win the second prize?
Multiplication of the probabilities, thus:
[tex]p = P(A) \times P(B) = \frac{10}{100} \times \frac{10}{99} = \frac{10\times10}{100\times99} = 0.0101[/tex]
0.0101 = 1.01% probability that your friend wins the first prize and you win the second prize.
A similar question is given at https://brainly.com/question/22281693
