Answer:
[tex](f+g)(x)=x^2-x-3[/tex]
Step-by-step explanation:
We have [tex]f(x)=2x-1[/tex] and [tex]g(x)=x^2-3x-2[/tex]
Recall that [tex]f+g[/tex] is defined by [tex](f+g)(x)=f(x)+g(x)[/tex], therefore
[tex](f+g)(x)=f(x)+g(x)=2x-1+x^2-3x-2=x^2-x-3[/tex]