When the object is submerged in methanol, it displaces an amount of methanol with weight 1.052 N, i.e. with mass = (1.052 N)/g ≈ 107.347 g. With a density of 0.8 g/cm³, this means the displaced methanol and hence the object itself have a volume of
v ≈ (107.347 g) / (0.8 g/cm³) ≈ 134.184 cm³
Likewise, when submerged in benzene, the object displaces 0.951 N of benzene, whose mass is (0.951 N)/g ≈ 97.041 g with the same volume as the object. So the density d of benzene is
d ≈ (97.041 g) / (134.184 cm³) ≈ 0.723 g/cm³
