Respuesta :

mhanifa

Answer:

Given a cube with the side of 7 in

Base area:

  • B = a² = 7² = 49 in²

Perimeter:

  • P = 4a = 4*7 = 28 in

Height:

  • H = a = 7 in

Lateral area:

  • LA = 4a² = 4*49 = 196 in²

Surface area:

  • SA = 6a² = 6*49 = 294 in²

Volume:

  • V = a³ = 7³ = 343 in³
  • Side=a=7in

Area of base:-

[tex]\\ \sf\longmapsto a^2=7^2=49in^2[/tex]

Perimeter :-

[tex]\\ \sf\longmapsto 4a=4(7)=28in[/tex]

Height:-

As its a cube height=side=7in

Lateral surface area :-

[tex]\\ \sf\longmapsto 4a^2=4(7^2)=4(49)=196in^2[/tex]

Total Surface Area:-

[tex]\\ \sf\longmapsto 6a^2=6(7^2)=6(49)=294in^2[/tex]

Volume:-

[tex]\\ \sf\longmapsto a^3=7^3=343in^3[/tex]

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