Find the constant C such that x ^ 3 - 3x + 5 <= C where x in[0,3] 18 23 14 17 21
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Plug in maximum value of x (3) and see what you get. The maximum value of the expression when plugged in is C.
[tex]3^3-3\cdot3+5=C[/tex]
[tex]27-9+5=C\implies 23=C[/tex]
Now that means,
[tex]x^3-3x+5\leq 23[/tex] for any x in [tex][0,3][/tex]
Hope this helps :)