Point O is the centroid of triangle ABC. If OD=3x -2 and OC= 5x, find x.
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At centroid medians bisect each other in the ratio 2:1
[tex]\\ \sf\longmapsto OC=2(OD)[/tex]
[tex]\\ \sf\longmapsto 2(3x-2)=5x[/tex]
[tex]\\ \sf\longmapsto 6x-4=5x[/tex]
[tex]\\ \sf\longmapsto 6x-5x=4[/tex]
[tex]\\ \sf\longmapsto x=4[/tex]
The value of x is 4, when we are given O is the centroid of the triangle ABC, OD = 3x - 2, and OC = 5x.
The center of the thing is represented by its centroid. The centroid of a triangle is the location where the triangle's three medians connect. The junction of all three medians is another definition for it. The median is a line that connects the middle of a side to the triangle's opposite vertex. The median is divided by the centroid of the triangle in a ratio of 2:1.
In the question, we are given that O is the centroid of triangle ABC, and are asked to find the value of x, for which OD = 3x - 2, and OC = 5x.
We know that the median is divided by the centroid of the triangle in a ratio of 2:1.
Thus, the median CD is divided by the ratio of 2:1 as,
2/1 = OC/OD,
or, 2/1 = (5x)/(3x - 2),
or, 2(3x - 2) = 1(5x) {Cross-multiplying},
or, 6x - 4 = 5x,
or, 6x - 5x = 4,
or, x = 4.
Thus, the value of x is 4, when we are given O is the centroid of the triangle ABC, OD = 3x - 2, and OC = 5x.
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