The perimeter of a triangle is the summation of the three sides of the triangle. Base on the assumed values, the length of side BD is 2.
For [tex]\triangle ACD[/tex], the sides are: AC, AD and CD
So, the perimeter is:
[tex]P_{\triangle ACD} = AC + AD + CD[/tex]
For [tex]\triangle ABD[/tex], the sides are: AB, AD and BD
So, the perimeter is:
[tex]P_{\triangle ABD} = AB + AD + BD[/tex]
The difference in the perimeters is:
[tex]P_{\triangle ACD} - P_{\triangle ABD} =1 + \sqrt 3[/tex]
So, we have:
[tex](AC + AD + CD) - ( AB + AD + BD) =1 + \sqrt 3[/tex]
Open brackets
[tex]AC + AD + CD - AB - AD - BD =1 + \sqrt 3[/tex]
Evaluate like terms
[tex]AC + CD - AB - BD =1 + \sqrt 3[/tex]
Make BD the subject
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex]
The solution cannot be completed because the side lengths of [tex]\triangle ACD[/tex] and [tex]\triangle ABD[/tex] are not given; so, I will assume the following values.
[tex]AC =2; CD = 1; AB = \sqrt 3[/tex]
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex] becomes
[tex]BD = 2 + 1 + \sqrt 3 - (1 + \sqrt 3)[/tex]
Open bracket
[tex]BD = 2 + 1 + \sqrt 3 - 1 - \sqrt 3[/tex]
Evaluate like terms
[tex]BD = 2[/tex]
Base on the assumed values, the length of side BD is 2.
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