Answer:
7. Ans ;
[tex] \frac{41}{3} < 14 < \sqrt{200} [/tex]
8. Ans ;
[tex]0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } [/tex]
Step-by-step explanation:
7. Ans ;
[tex] \sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6[/tex]
So ;
[tex] \frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1[/tex]
8. Ans ;
[tex] \frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6[/tex]
So ;
[tex]0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75[/tex]
I hope I helped you^_^
