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blocks x and y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block x is 10 kg and that of block y is 5 kg. the magnitude of force of friction on blocks x and y is 8.0 N and 4.0N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N(right) acts on block per illustration below.

blocks x and y are attached to each other by a light rope and can slide along a horizontal surface Mass of block x is 10 kg and that of block y is 5 kg the magn class=

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onyebuchinnaji

Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.

The given parameters:

mass of block x = 10 kg

mass of block y = 5 kg

magnitude of the frictional force of block x = 8 N

magnitude of the frictional force of block y = 4 N

the applied force to the right = 40 N

To find:

  • the action-reaction forces that the blocks exert on each other

The block y pulls block x to the left with the following reaction forces;

Force of block y = force due to its own weight + frictional force

  • Reaction Force of block y = mg  + 4 N

where;

g is the acceleration due to gravity = 9.81 m/s²

  • Reaction Force of block y = (5 x 9.81) + 4
  • Reaction Force of block y = 49.1 + 4
  • Reaction Force of block y = 53.1 N

Thus, block y reacts on block x with a force of 53.1 N

The block x acts on block y towards the right direction with following forces;

Force of block x on y =  force due to its own weight + frictional force + applied force to the right

  • Force of block x on y = (mg) + (8 N) + (40 N)
  • Force of block x on y = (10 x 9.81) + (48)
  • Force of block x on y = 98.1 + 48
  • Force of block x on y = 146.1 N

Thus, block x acts on block y with a force of 146.1 N

Learn more here: https://brainly.com/question/20709953

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