Answer:
12
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
PC * PA = PB^2
(PA+AC) * PA = PB^2
(4+32) * 4 = PB^2
36*4 = PB^2
144 = PB^2
Taking the square root of each side
sqrt(144) = sqrt(PB^2)
12= PB
Answer:
a
Step-by-step explanation:
Given a tangent and a secant to a circle from an external point, then
The square of the tangent is equal to the product of the external part and the whole of the secant , that is
PB² = PA × PC = 4(4 + 32) = 4 × 36 = 144 ( take square root of both sides )
PB = [tex]\sqrt{144}[/tex] = 12 → a
