The height of the window above the ground is 11.025m
The first step is to write out the parameters given in the question
U(initial velocity)= 0
Time= 1.5 seconds
Acceleration due to gravity= 9.8
Therefore the height of the window can be calculated as follows
S= ut + 1/2gt²
= 0(1.5) + 1/2(9.8)(1.5²)
= 0 + 1/2(9.8)(2.25)
= 1/2(22.05)
= 0.5×22.05
= 11.025
Hence the height of the window above the ground is 11.025m
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