Answer:
(i) a = 2
b = -1
c = -1
(ii) x= 1
Step-by-step explanation:
Step 1: Factorise
[tex]f(x) = 2(x^{2} -2x+\frac{1}{2})[/tex]
Step 2: Use the complete square method.
[tex]f(x)=2(x^{2} -2x+(\frac{-2}{2})^{2} + \frac{1}{2} - (\frac{-2}{2})^{2} )[/tex]
Step 3: Have it to [tex]a(x+b)^{2} +c[/tex]
[tex]f(x)=2((x-1)^{2} -\frac{1}{2} )\\ = 2(x-1)^{2} -1[/tex]
Line of symmetry:
To find line of symmetry, we use -b/2a formula.
Based from [tex]2x^{2} -4x+1[/tex]:
a=2, b=-4
-b/2a = -(-4)/2(2) = 1
