Bo paid bills with 1/2 of his paycheck snd put 1/5 of the remainder in savings. The rest of his paycheck he divided equally among the college accounts of his 3 children.
A. what fraction of his paycheck went into each childs account?
B. If Bo deposited $400 in each childs account, how much money was in Bo's original paycheck?

Respuesta :

1/2 + 1/5(1/2) = 1/2 + 1/10 = 5/10 + 1/10 = 6/10....this leaves 4/10 (reduces to 2/5) for his children.

(2/5) / 3 = 2/5 * 1/3 = 2/15 for each child <== A

400 in each childs account.....thats (400 * 3) = 1200 ...
2/5 of what is 1200 =
2/5x = 1200
x = 1200 * 5/2
x = 6000/2
x = 3000 <== B

check...
total pay is 3000
1/2 for bills.....- 1500
1/5(-1500) = -1500/5 = -300 ....for savings
3000 - (1500 + 300) = 3000 - 1800 = 1200...remaining for the children
1200/3 = 400 ...for each child.

so ur answers are :
A. 2/15 in each childs account
B. original paycheck = $ 3000


Answer:

Bo's original paycheck is $3000.

Step-by-step explanation:

Bo paid bills with 1/2 of his paycheck and put 1/5 of the remainder in savings.

The rest of his paycheck he divided equally among the college accounts of his 3 children.

Let his earnings be x

So, [tex]x-\frac{1}{2}[/tex]went in bills.

And he put 1/5 of the remainder in savings.

[tex]\frac{1}{5}(\frac{1}{2} ) =\frac{1}{10}[/tex]

He put [tex]\frac{1}{10}[/tex] of x in savings

Adding the bill and remainder amount = [tex]\frac{1}{2} +\frac{1}{0}[/tex]

= [tex]\frac{5+1}{10}=\frac{6}{10}[/tex]

So, left amount was = [tex]1-\frac{6}{10}=\frac{10-6}{10}=\frac{4}{10}=\frac{2}{5}[/tex]

This 2/5 was divided equally among 3 kids making it :

[tex]\frac{\frac{2}{5} }{3} =\frac{2}{15}[/tex]

Now, as given, Bo deposited $400 in 3 kids accounts. This gives [tex]3\times400=1200[/tex] in total in kids account.

We know $1200 is 2/5 of total income or x

So, [tex]\frac{2x}{5}=1200[/tex]

[tex]2x=6000[/tex]

x = $3000

Hence, Bo's original paycheck is $3000.