The magnitude and the direction of the Jet's acceleration is 3.53 m/s² south.
The given parameters;
final velocity of the jet, v = 81.9 m/s
distance traveled, s = 949 m
The magnitude and the direction of the Jet's acceleration is calculated as;
v² = u² + 2as
where;
- v is the final velocity of the Jet
- u is the initial velocity of the jet
- s is the distance traveled by the train
- a is the acceleration of the train
Substitute the given parameters and solve for a;
(81.9)² = 0 + (2 x 949)a
6707.61 = 1898a
[tex]a = \frac{6707.61}{1898} \\\\a = 3.53 \ m/s^2[/tex] south
Thus, the magnitude and the direction of the Jet's acceleration is 3.53 m/s² south.
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