Answer:
[tex] {4x}^{2} + 2x + 1[/tex]
Step-by-step explanation:
the most handy way to solve the question is Polynomial long division which is done below:
[tex] \begin{array}{ccc} \qquad {4x}^{2} + 2x + 1 \\ \hline x - 4 \Bigg)4 {x}^{3} - {14x}^{2} - 7x - 4 \\ - {4x}^{3} + 16 {x}^{2} \\ \hline \qquad \qquad \qquad {2x}^{2} - 7x - 4 \\ \qquad \qquad- {2x}^{2} + 8x \\ \hline \qquad \qquad \qquad \qquad \qquad x - 4 \\ \qquad \qquad \qquad \qquad \qquad - x + 4 \\ \hline\qquad \qquad \qquad \qquad \qquad0 \end{array}[/tex]
since our remainder is 0 we'll put the answer in P(x) form only
note: please see the answer in the brainly app for a better view
