Answer:
1.89 × 10^-11 M
Explanation:
Recall that;
[H^+] [OH^-] = 1 × 10^-14
[H^+] = concentration of hydronium ions
[OH^-] = concentration of hydroxide ion
Where [OH^-] = 5.3 × 10−4 M
[H^+]= 1 × 10^-14/5.3 × 10−4
[H^+]= 1.89 × 10^-11 M
Milk of magnesia, with a concentration of hydroxide ions of 5.3 × 10⁻⁴ M, has a concentration of hydronium ions of 1.9 × 10⁻¹¹ M.
Milk of magnesia (Mg(OH)₂) is an antacid, in which the concentration of hydroxide ions is 5.3 × 10⁻⁴ M.
We can calculate the concentration of hydronium ions at 25°C using the following expression.
[tex][H_3O^{+} ][OH^{-} ] = Kw = 1.0 \times 10^{-14} \\\\[H_3O^{+} ] = \frac{1.0 \times 10^{-14} }{[OH^{-} ]} = \frac{1.0 \times 10^{-14} }{5.3 \times 10^{-4} } = 1.9 \times 10^{-11} M[/tex]
where,
Since [H₃O⁺] < 10⁻⁷ M, the milk of magnesia is basic.
Milk of magnesia, with a concentration of hydroxide ions of 5.3 × 10⁻⁴ M, has a concentration of hydronium ions of 1.9 × 10⁻¹¹ M.
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