A motorist travels 90 miles at a rate of 20 miles per hour. If he returns the same distance at a rate of 40 miles per hour, what is the average speed for the entire trip, in miles per hour? (Pls explain throughly with your answer)

Respuesta :

Answer:

80/3

Step-by-step explanation:

same distance is covered at different speed , avg speed= 2ab/a+b

= 2*20*40/60

= 80/3

Answer:

[tex]\frac{80}{3}\text{ mph}[/tex]

Step-by-step explanation:

We can use the formula [tex]d=rt[/tex] (distance  = rate * time) to solve this problem.

If the motorist is travelling 90 miles to and back on a trip, he has travelled [tex]90+90=180[/tex] miles total. This represents [tex]d[/tex] in our formula.

Now we need to find the total time.

On the first trip, it's given that the motorist travels at a rate of 20 mph. Therefore, the time this trip took to travel 90 miles is:

[tex]90=20t,\\t=\frac{90}{20}=\frac{9}{2}=4.5[/tex] hours

On the second trip back, he travels the same distance (90 miles) at a rate of 40 mph. Therefore, the time the trip took is:

[tex]90=40t,\\t=\frac{90}{40}=\frac{9}{4}=2.25[/tex] hours

Therefore, the total time is [tex]4.5+2.25=6.75[/tex] hours.

Now can calculate the average speed of the entire trip:

[tex]180=6.75r,\\r=\frac{180}{6.75}=\frac{180}{\frac{27}{4}}=180\cdot \frac{4}{27}=\boxed{\frac{80}{3}\text{ mph}}[/tex]