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An inductor has an inductance of 0.053 H. The voltage across this inductor is 48 V and has a frequency of 270 Hz. What is the current in the inductor?

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abidemiokin

Answer:

3.004A

Explanation:

The voltage across an inductor is expressed as:

[tex]V=IX_L\\V=I(2\pi fL)[/tex]

Given

f = 270Hz

V = 48V

L =0.053 H

Get the current

270 = I (2*3.14*270*0.053)

270 = 89.8668I

I = 270/89.8668

I = 3.004A

Hence the current in the inductor is 3.004A

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