The shiny silver mouse has a population mean size of 8.3 cm and and a population standard deviation of 1.2 cm. If one individual is sampled from the population what is the probability that it will be greater than 9 cm

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Answer:

41.67%

Step-by-step explanation:

[tex]Z = \frac{x-\alpha}{\sigma}[/tex]     9-8.3 = 0.7/1.2 = 0.5833  1-0.5833 = 0.4167*10 = 41.67%

The probability of the individual sample which is greater then 9 cm is 0.2799601 .

What is probability?

'Probability is the extent to which an event is likely to occur, measured by the ratio of the favorable cases to the total number of cases possible.'

According to the given problem,

μ = 8.3 cm

σ = 1.2 cm

X ≈ N[tex](0,1)P(X < x )[/tex]

= P(Z = X - μ / σ)

here , X ≈ N (8.3 , [tex](1.2)^2)P(X > 9)[/tex]

= P[tex](Z > \frac{9-8.3}{1.2})[/tex]

⇒ P[tex](Z>0.583333)[/tex]

⇒ 1 - P[tex](Z<0.583333)[/tex]

⇒ 1 - 0.7200399 [ for greater surface area of the bell-curve ]

⇒ 0.2799601

Hence, we can conclude, the probability of individual sample is 0.2799601 .

Learn more about the probability here :brainly.com/question/23211929?#SPJ2