Respuesta :

mistressofdark

Given,

initial velocity, u = 10m/s

acceleration, a = -8m/s²

time, t = 2s

[tex]we \: know \: that \\ s = ut + \frac{1}{2}a {t}^{2} \\ = > s = (10m {s}^{ - 1} \times 2s) + ( \frac{1}{2} \times (- 8m {s}^{ - 2}) \times {(2s)}^{2}) \\ = >s = 10m + (- 8m) \\ = > s = 2m[/tex]

This is the answer.

Hope it helps!!

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