Answer:
The sum of the first 50 is 5200
Step-by-step explanation:The given sequence is a linear sequence.
So, first we calculate the common difference
d=t2-t1
d=10-6=4
The sum of the first 50 terms is then calculated using: sorry it wont let me copy and paste my explo and im lazy
Answer:
5,200
Step-by-step explanation:
6, 10, 14, ...
Sum = [ number of terms(first term+last term) ] / 2
-we know there are 50 terms
-we now the first term is 6
-we need to find the last term
last term = first term + (n-1)* difference between first and second term
last term = 6 + (50-1) * (10-6)
last term = 6 + 49*4 = 202
Sum = [ number of terms(first term+last term) ] / 2
Sum = [ 50 ( 6 + 202) ] / 2 = 5,200
