Toyotas manufactured in the 1990s have a mean lifetime of 22.6 years, with a standard deviation of 3.1 years. The distribution of their lifetimes is not assumed to be symmetric. Between what two lifetimes does Chebyshev's Theorem guarantee that we will find at least 95% of the Toyotas

Respuesta :

Answer:

The answer is "8.74 and 36.46 years"

Step-by-step explanation:

Mean (life-time)=22.6 years

standard deviation= 3.1 years

We must find out how many standard deviations are 95% of the data.  

[tex]1 - \frac{1}{k^2} = 0.95\\\\1 - 0.95 = \frac{1}{k^2}\\\\\frac{1}{k^2} = 0.05\\\\\frac{1}{0.05} =k^2\\\\k^2 = 20\\\\ k = 4.47[/tex]

Calculating the lower limit and upper limit:

[tex]Lower\ limit = 22.6 - 4.47(3.1) = 22.6 - 13.86 = 8.74\\\\Upper\ limit = 22.6 + 4.47(3.1) = 22.6 + 13.86 = 36.46[/tex]

Limit is 8.74 years to 36.46 years