Please help out would really appreciate it
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Answer:
Step-by-step explanation:
1. Apply the Pythagoras theorem to determine the value of x, we have;
[tex]/Hyp/^{2}[/tex] = [tex]/Adj 1/^{2}[/tex] + [tex]/Adj 2/^{2}[/tex]
[tex]x^{2}[/tex] = [tex]15^{2}[/tex] + [tex]8^{2}[/tex]
= 289
x = [tex]\sqrt{289}[/tex]
x = 17
2. Trigonometric ratios of <D.
i. Sin <D = [tex]\frac{opposite}{hypotenuse}[/tex]
= [tex]\frac{8}{17}[/tex]
ii. Cos <D = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
= [tex]\frac{15}{17}[/tex]
iii. Tan <D = [tex]\frac{Opposite}{Adjacent}[/tex]
= [tex]\frac{8}{15}[/tex]
3. Trigonometric ratios of <F.
i. Sin <F = [tex]\frac{opposite}{hypotenuse}[/tex]
= [tex]\frac{15}{17}[/tex]
ii. Cos <F = [tex]\frac{Adjacent}{Hypotenuse}[/tex]
= [tex]\frac{8}{17}[/tex]
iii. Tan <F = [tex]\frac{Opposite}{Adjacent}[/tex]
= [tex]\frac{15}{8}[/tex]