Answer:
Following are the solution to the given question:
Explanation:
In the aqueous solution of [tex]Hg^{2+}[/tex] ion is used to represent a [tex][Hg(H_2O)_4]^{2+}[/tex].
It is used to form a complex with iodide ions as [tex][Hgl_4]^{2-}[/tex].
Conversion reaction:
[tex][Hg(H_2O)_4]^{2+} +4I^{-} \to [HgI_4]^{2-}+4H_20[/tex]
Following are the formation constants:
[tex]k_f=\frac{[HgI_4]^{2-}}{[Hg(H_2O)_4]^{2+} [I^{-}]^4}[/tex]
Following are the first step to the conversion:
[tex][Hg(H_2O)_4]^{2+} +I^{-} \to [HgI(H_2O)_3]^{+}+H_20[/tex]