Answer:
[tex]\boxed{ \sf Cuts \ x-axis \ at \ (9,0 ).}[/tex]
[tex]\boxed{ \sf Cuts \ y-axis \ at \ (0,6).}[/tex]
Step-by-step explanation:
We need to graph a linear equation and we need to find the point on which it crosses the x and y axis . The given equation is,
[tex]\sf\longrightarrow 2x + 3y = 18 [/tex]
For graphing it's line we need at least two points . hair we can find out the points on which it cuts the x and y axis and then using those two points we can plot its graph.
Step 1 : Put x = 0 in the equation :-
[tex]\sf\longrightarrow 2*0 + 3y = 18 [/tex]
Simplify ,
[tex]\sf\longrightarrow 0 + 3y = 18[/tex]
Add ,
[tex]\sf\longrightarrow 3y = 18[/tex]
Divide both sides by 3 ,
[tex]\sf\longrightarrow \underline{\purple{ y = 6}}[/tex]
Step 2: Put y = 0 in the equation :-
[tex]\sf\longrightarrow 2x + 3*0 = 18 [/tex]
Simplify ,
[tex]\sf\longrightarrow 2x = 18 [/tex]
Divide both sides by 2 ,
[tex]\sf\longrightarrow \underline {\purple{x = 9}}[/tex]
Hence the line cuts y axis on (0,6) and on x axis at (9,0) . Now these two points plot the graph . [ Graph is in attachment ]
