Let 0 be an acute angle of a right triangle. Evaluate the other five trigonometric functions of 0.
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Answer:
sin θ = (√119)/12
tan θ = (√119)/5
csc θ = 12/(√119)
cot θ = 5/(√119)
Five trigonometric functions of θ are
sinθ = [tex]\frac{\sqrt{119} }{12}[/tex]cosθ = [tex]\frac{5}{12}[/tex]tanθ = [tex]\frac{\sqrt{119} }{5}[/tex]cosecθ = [tex]\frac{12}{\sqrt{119} }[/tex]secθ = [tex]\frac{12}{5}[/tex]cotθ = [tex]\frac{5}{\sqrt{119} }[/tex]
"The trigonometric functions of θ are functions of an angle. sine, cosine, and tangent are familiar trigonometric functions. The trigonometric functions relates the angles of a triangle to the length of its side."
Let θ be an acute angle of a right angle triangle
"An acute angle ("acute" meaning "small") is an angle smaller than a right angle. The range of an acute angle is between 0 and 90 degrees."
"A right angled triangle is a triangle in which one angle is a right angle (that is, a 90-degree angle).
"The side opposite the right angle is called the 'hypotenuse'. The hypotenuse is always the longest side. The sum of the other two interior angles is equal to 90°."
"An 'opposite' side is the one across from a given angle."
"An 'adjacent' side is next to a given angle. We use special words to describe the sides of right triangles."
we have,
cosθ = [tex]\frac{5}{12}[/tex]
secθ = [tex]\frac{12}{5}[/tex]
Hypotenuse side = 12
Adjacent side = 5
∴ Opposite side = [tex]\sqrt{hyp^{2}-adj^{2} }[/tex]= [tex]\sqrt{12^{2}-5^{2} }[/tex] = [tex]\sqrt{119}[/tex]
sinθ = [tex]\frac{opp}{hyp}[/tex] = [tex]\frac{\sqrt{119} }{12}[/tex]
tanθ = [tex]\frac{opp}{adj}[/tex] = [tex]\frac{\sqrt{119} }{5}[/tex]
cosecθ = [tex]\frac{hyp}{opp}[/tex] = [tex]\frac{12}{\sqrt{119} }[/tex]
cotθ = [tex]\frac{adj}{opp}[/tex] = [tex]\frac{5}{\sqrt{119} }[/tex]
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