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5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
color (the name indium is derived from the word indigo). The emitted photons that give rise to this
color
have energies of 4.405 x 10^-19J. Calculate the wavelength of this radiation in nanometers.

Respuesta :

sebassandin

Answer:

[tex]\lambda=451nm[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

[tex]E=\frac{hC}{\lambda }[/tex]

Thus, we solve for the wavelength as shown below:

[tex]\lambda=\frac{hC}{ E}[/tex]

And finally plug in the energy, Planck's constant and speed of light to obtain:

[tex]\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm[/tex]

Regards!

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