Given:
Perimeter of a rectangle = 24
Width of the rectangle = x
Length of the rectangle = y
To find:
The length of the rectangle in terms of x and possible values of x and y.
Solution:
The perimeter of a rectangle is:
[tex]P=2(l+w)[/tex]
Where, l is the length and w is the width.
Putting [tex]P=24,l=y,w=x[/tex], we get
[tex]24=2(y+x)[/tex]
Divide both sides by 2.
[tex]12=y+x[/tex]
[tex]12-x=y[/tex]
The possible values of x are 1, 2, 3, 4, 6, 7, 8, 9, 10, 11 and the respective possible y values are 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1.
Therefore, the value of y in terms of x is [tex]y=12-x[/tex].
