Answer:
[tex]g(x) = 6(2)^{x -8}+ 4[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 6(2)^{x - 1}+ 4[/tex]
Required
Find g(x)
From the question, f(x) is translated 7 units left;
The rule of translation is: [tex](x,y) \to (x-7,y)[/tex]
So, we have:
[tex]g(x) = f(x - 7)[/tex]
[tex]g(x) = 6(2)^{x -7- 1}+ 4[/tex]
[tex]g(x) = 6(2)^{x -8}+ 4[/tex]
