Given:
The graph of a line.
To find:
The point-slope form of the given line.
Solution:
From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\dfrac{-1-5}{0-1}[/tex]
[tex]m=\dfrac{-6}{-1}[/tex]
[tex]m=6[/tex]
The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-5=6(x-1)[/tex]
Therefore, the point-slope form is [tex]y-5=6(x-1)[/tex], slope is 6 and the point is (1,5).
