Respuesta :

Answer:

[tex] \large{ \tt{ ✽ \: S \: O \: L \: U \: T \: I \: O \: N: }}[/tex]

  • We're provided : Point A [ Let's suppose ] ( 0 , -3/5 ) and slope = -1 and we're asked to find out the equation of a line having these point and slope. Let A ( 0 , -3/5 ) be ( x₁ , y₁ ).Firstly , You'll have to know : y - y₁ = m ( x - x₁ )

[tex] \large{ \tt{✺ \: S \: O \: L \: V \: I \: N \: G \: ...}}[/tex]

[tex] ❁ \: \large{ \tt{y - y_{1} = m(x - x_{1} )}}[/tex]

[tex] \large{ \tt{⟶ \: y - ( - \frac{3}{5} ) = - 1(x - 0)}}[/tex]

[tex] \large{ \tt{⟶ \: y + \frac{3}{5} = - x + 0}}[/tex]

[tex] \large {\tt{⟶ \: \frac{5y + 3}{5 } = - x }}[/tex]

[tex] \large{ \tt{⟶ \: 5y + 3 = - 5x}}[/tex]

[tex] \boxed{\large{ \tt{⟶5x + 5y + 3 = 0}}}[/tex]

  • Hence , 5x + 5y + 3 = 0 is the required equation.

  • Hope I helped! Let me know if you have any question regarding my answer and also don't hesitate to reach out to me if you need any other help! :)

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