Answer:
[tex]C = 5[/tex]
Step-by-step explanation:
Given
[tex]F = \frac{9}{5}C + 32[/tex]
Required
Find C when [tex]F = 41[/tex]
We have:
[tex]F = \frac{9}{5}C + 32[/tex]
Substitute 41 for F
[tex]41 = \frac{9}{5}C + 32[/tex]
Collect like terms
[tex]\frac{9}{5}C = 41- 32[/tex]
[tex]\frac{9}{5}C = 9[/tex]
Multiply both sides by 5/9
[tex]C = 9 * \frac{5}{9}[/tex]
[tex]C = 5[/tex]