Respuesta :
First even =24
Second even =26
let 2x be the first even integer
let 2x+2 be the second even integer
2x+(2x+2)=50
4x=48
x=12
First even integer
2x=2(12)=24
Second even integer
2x+2=2(12)+2=26
Second even =26
let 2x be the first even integer
let 2x+2 be the second even integer
2x+(2x+2)=50
4x=48
x=12
First even integer
2x=2(12)=24
Second even integer
2x+2=2(12)+2=26
Answer:
First even = 24
Second even = 26
Step-by-step explanation:
let x be the first even integer.
let 2x be the second even integer.
[tex]x + 2x = 50[/tex]
[tex]x + x = 50 - 2 [/tex]
[tex]2x =48[/tex]
[tex]x = \frac{48}{2} [/tex]
[tex] x = 24[/tex]
Therefore, The first even number is 24.
[tex]second \: \: number= 50 - x \\ = 50-24 \\ = 26[/tex]
Therefore, The second even number is 26.