Answer:
[tex]a_n=a_{n-1}+8,n\geq 1[/tex]
[tex]a_1=-11[/tex]
Step-by-step explanation:
We are given that a sequence
-11,-3,5,13,...
[tex]a=a_1=-11[/tex]
[tex]a_2=-3[/tex]
[tex]a_3=5[/tex]
[tex]a_2-a_1=-3-(-11)=-3+11=8[/tex]
[tex]a_3-a_2=5-(-3)=5+3[/tex]
[tex]a_3-a_2=8[/tex]
Common difference between two consecutive terms is equal.
Hence, the sequence is Arithmetic.
Common difference, d=8
[tex]a_2=a_1+8=-3[/tex]
[tex]a_3=a_2+8=5[/tex]
[tex]a_4=a_3+8=13[/tex]
:
:
:
[tex]a_n=a_{n-1}+8, n\geq 1[/tex]
[tex]a_1=-11[/tex]
