Given:
Diameter of the tennis ball = 14 inches.
Three tennis balls are fit in a cylindrical tennis ball cane.
To find:
The volume of air left between the balls and the cane.
Solution:
Diameter of the tennis ball = 14 inches.
Radius of the tennis ball = 7 inches
Radius of tennis ball is equal to radius of cane. So,
Radius of the cane = 7 inches
Height of cane is:
[tex]3\times 14=42[/tex] inches
Volume of a ball is:
[tex]V_1=\dfrac{4}{3}\pi r^3[/tex]
Where, r is the radius of the ball.
So, the volume of 3 ball is:
[tex]V_2=3\times V_1[/tex]
[tex]V_2=3\times \dfrac{4}{3}\times \dfrac{22}{7}\times (7)^3[/tex]
[tex]V_2=4312[/tex]
Volume of the cane is:
[tex]V_3=\pi r^2h[/tex]
Where, r is the radius of the cane and h is the height of the cane.
[tex]V_3=\dfrac{22}{7}\times (7)^2\times 42[/tex]
[tex]V_3=6468[/tex]
Now, the volume of air left between the balls and the cane is:
[tex]V=V_3-V_2[/tex]
[tex]V=6468-4312[/tex]
[tex]V=2156[/tex]
Therefore, the volume of air left between the balls and the cane is 2156 cubic inches.
