Answer:
1984
Explanation:
Given the formula;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2 = half life of the radioactive isotope
t= age of the wine
Ao= initial activity of the wine
A= activity of the at time = t
0.693/12.3 = 2.303/t log (5.5/0.688)
0.693/12.3 = 2.079/t
0.056 = 2.079/t
t= 2.079/0.056
t= 37 years
The wine was produced 37 years ago which means that it was produced in the year 1984
The wine has been produced in the year 1984.
Half-life can be defined as the time required by the substance to reduce to half of its initial concentration.
The decay of wine per minute has been = 0.688/minute
The half-life of the sample has been = 12.3
The decay of freshwater has been= 5.5 decay/minute
k can be given as:
k = [tex]\rm \dfrac{0.693}{Half-life}[/tex]
k = [tex]\rm \dfrac{0.693}{12.3}[/tex]
k = 0.056 years
The time for the decay can be calculated as:
t = [tex]\rm \dfrac{2.303}{k}\;log\; \dfrac{a}{a\;-\;x}[/tex]
t = [tex]\rm \dfrac{2.303}{0.056}\;\times\;log\;\dfrac{5.5}{0.688}[/tex]
t = 37 years
The wine has been produced 37 years ago. The present year has been 2021. The year of wine production has been:
Year of wine production = 2021 - 37
Year of wine production = 1984.
The wine has been produced in the year 1984.
For more information about tritium dating, refer to the link:
https://brainly.com/question/2990708
