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Calculate percent yield when you start with 0.78 grams of camphor and end with 0.23 grams of iso/borneol. The molecular weight of camphor is 152.23 g/mol, and the molecular weight of iso/borneol is 154.25 g/mol.

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Answer:

29.1%

Explanation:

First we convert 0.78 g of camphor to moles, using its molar mass:

  • 0.78 g ÷ 152.23 g/mol = 0.00512 mol camphor

Then we convert 0.23 g of isoborneol to moles, using its molar mass:

  • 0.23 g ÷ 154.25 g/mol = 0.00149 mol isoborneol

Finally we calculate the percent yield:

  • 0.00149 mol / 0.00512 mol * 100% = 29.1%

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