Answer:
The correct answer is "470.4 N".
Explanation:
Let the system moves downwards with acceleration "a",
then,
⇒ [tex]a = \frac{Net \ external \ force}{Net \ mass}[/tex]
[tex]=\frac{(m_2+m)g}{(m_2+m_1+m)}[/tex]
[tex]=\frac{440+60}{(440+2000+60)}[/tex]
[tex]=\frac{500\times 9.8}{2500}[/tex]
[tex]=1.96 \ m/s^2[/tex]
The apparent weight will be:
⇒ [tex]mg-F_A=ma[/tex]
or,
⇒ [tex]F_A=mg-ma[/tex]
[tex]=m(g-a)[/tex]
By substituting the values, we get
[tex]=60(9.8-1.96)[/tex]
[tex]=470.4 \ N[/tex]
