Answer:
a. -1
e. 5/4
Step-by-step explanation:
Hi there!
The quadratic formula: [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] where the given quadratic is in the form [tex]ax^2+bx+c=0[/tex]
From the given equation [tex]4x^2-x-5 = 0[/tex], we can identify the values of a, b, and c:
a=4
b=-1
c=-5
Plug these values into the quadratic formula:
[tex]x=\frac{-(-1)\pm\sqrt{(-1)^2-4(4)(-5)}}{2(4)}\\x=\frac{1\pm\sqrt{81}}{8}[/tex]
[tex]x=\frac{1\pm9}{8}[/tex]
[tex]x=\frac{1+9}{8}= \frac{5}{4} \\x=\frac{1-9}{8} = -1[/tex]
Therefore, the solutions to the quadratic are 5/4 or 1.
I hope this helps!
