The graph of a quadratic function has x-intercepts of -7and -1 ,and passes through the point (-4,36). determine the equation of the quadratic function in the form f(x)=a(x-m)(x-n)

Respuesta :

Answer:

[tex]f(x) = -4(x+7)(x+1)[/tex]

Step-by-step explanation:

Quadratic equation:

A quadratic equation, with roots(x-intercepts) at [tex]x_1[/tex] and [tex]x_2[/tex], and leading coefficient a, is given by:

[tex]f(x) = a(x - x_1)(x - x_2)[/tex]

Has x-intercepts of -7 and -1

So [tex]x_1 = -7, x_2 = -1[/tex]. Thus

[tex]f(x) = a(x - (-7))(x - (-1)) = a(x+7)(x+1)[/tex]

Passes through the point (-4,36).

This means that when [tex]x = -4, y = 36[/tex], and we use this to find the leading coefficient.

[tex]36 = a(-4+7)(-4+1)[/tex]

[tex]a(3)(-3) = 36[/tex]

[tex]-9a = 36[/tex]

[tex]a = -\frac{36}{9}[/tex]

[tex]a = -4[/tex]

So

[tex]f(x) = -4(x+7)(x+1)[/tex]