Answer: There are 0.024 moles of gas are present in the container.
Explanation:
Given: Temperature = [tex]25^{o}C[/tex] = (25 + 273) K = 298 K
Pressure = 1.7 atm
Volume = 345 mL (1 mL = 0.001 L) = 0.345 L
Formula used is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T= temperature
Substitute the values into above formula as follows.
[tex]PV = nRT\\1.7 atm \times 0.345 L = n \times 0.0821 L atm/mol K \times 298 K\\n = \frac{1.7 atm \times 0.345 L}{0.0821 L atm/mol K \times 298 K}\\= \frac{0.5865}{24.4658} mol\\= 0.024 mol[/tex]
Thus, we can conclude that there are 0.024 moles of gas are present in the container.
