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Measure the length of AC. Use coordinate algebra to locate a point E on AC such that the ratio of AE to EC is equal to the ratio of AD to DB. Show how you derived your answer. (Hint: Let x and AC − x represent the two line segments that make up AC .)

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If  AC is 13 unit,  then AC = 4.875 (5.875, 1) then the ratio of the segment  via which E divides line AC is said to be equal to the ratio of AD and DB.

What is the line segment about?

In the image attached, The length of AC = 13.

Take length of AE = x.

Take length of EC = 13 x.

The ratio of AE to EC = 0.6.

The [tex]\frac{AC}{EC}[/tex]

x = 0.6(13 - x)

x = 7.8 - 0.6x

1.6x = 7.8

x = 4.875

Therefore, AC = 4.875

Since E is found on AC so  EC = 13 -x = 13 - 4.875 = 8.125

Therefore,

AC = 4.875

EC = 8.125

See full question below

Line AC is 13 units long. Use coordinate algebra to locate a point E on Line AC such that the ratio of AE to EC is equal to the ratio of AD to DB which is 0.6. Show how you derived your answer. (Hine: Let x and AC - x represent the two line segments that make up Line AC

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