Answer:
The probability that two randomly selected tulip bulbs are both red is 0.11
The probability that the first bulb selected is red and the second is yellow is 0.13
The probability that the first bulb selected is yellow and the second is red is 0.13
Step-by-step explanation:
A bag of 29 tulip bulbs contains:
10 red tulip bulbs
11 yellow tulip bulbs
8 purple tulip bulbs
Part 1:What is the probability that two randomly selected tulip bulbs are both red?
No. of red tulips = 10
So, probability of getting red tulip in first draw = [tex]\frac{\text{Favorable events}}{\text{Total events}}[/tex]
= [tex]\frac{10}{29}[/tex]
Since 1 bulb is drawn . So, total no. of bulbs remaining = 28
And that 1 bulb is drawn from red bulbs . So, remaining red bulbs = 9
So, probability of getting red bulb in second draw = [tex]\frac{9}{28}[/tex]
Thus the probability that two randomly selected tulip bulbs are both red:
= [tex]\frac{10}{29}\times\frac{9}{28}[/tex]
= [tex]\frac{45}{406}[/tex]
= [tex]0.11[/tex]
Hence the probability that two randomly selected tulip bulbs are both red is 0.11
Part 2: What is the probability that the first bulb selected is red and the second is yellow?
No. of red tulips = 10
So, probability of getting red tulip in first draw = [tex]\frac{\text{Favorable events}}{\text{Total events}}[/tex]
= [tex]\frac{10}{29}[/tex]
Since 1 bulb is drawn . So, total no. of bulbs remaining = 28
No. yellow bulbs =11
So, probability of getting yellow bulb in second draw = [tex]\frac{11}{28}[/tex]
Thus the probability that the first bulb selected is red and the second is yellow
= [tex]\frac{10}{29}\times\frac{11}{28}[/tex]
= [tex]\frac{55}{406}[/tex]
= [tex]0.13[/tex]
Hence the probability that the first bulb selected is red and the second is yellow is 0.13
Part 3: What is the probability that the first bulb selected is yellow and the second is red?
No. of yellow tulips = 11
So, probability of getting yellow tulip in first draw = [tex]\frac{\text{Favorable events}}{\text{Total events}}[/tex]
= [tex]\frac{11}{29}[/tex]
Since 1 bulb is drawn . So, total no. of bulbs remaining = 28
No. red bulbs =10
So, probability of getting red bulb in second draw = [tex]\frac{10}{28}[/tex]
Thus the probability that the first bulb selected is red and the second is yellow
= [tex]\frac{11}{29}\times\frac{10}{28}[/tex]
= [tex]\frac{55}{406}[/tex]
= [tex]0.13[/tex]
Hence the probability that the first bulb selected is yellow and the second is red is 0.13
