Answer:
[tex]\boxed{\sf sin\ C =\frac{40}{41}}[/tex]
Step-by-step explanation:
We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .
We know that the ratio of sine is perpendicular to hypontenuse .
[tex]\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}[/tex]
Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,
[tex]\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}[/tex]
Substitute the respective values ,
[tex]\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}[/tex]
Hence the required answer is 40/41.
