Answer: 0.5747
Step-by-step explanation:
Given: Average time to serve a customer[tex](\mu)=4.35[/tex] minutes
standard deviation of the service time [tex](\sigma)=[/tex] 2.5 minutes
coefficient of variation = [tex]\frac{\sigma}{\mu}[/tex]
[tex]=\dfrac{2.5}{4.35}\\\\=\dfrac{250}{435}\\\\=0.5747[/tex]
Hence, the required coefficient of variation= 0.5747
